Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 50

Answer

$-162\sqrt 2$

Work Step by Step

We know that the angle between two vectors is: $\theta =\cos^{-1} [ \dfrac{u \cdot v}{||u|| \space ||v|| }]$ Therefore, $\cos (\dfrac{3\pi}{4}) = \dfrac{u \cdot v}{(9)(36) }$ or, $u \cdot v= 324 \times (\dfrac{-\sqrt 2}{2})$ or, $u \cdot v=-162\sqrt 2$
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