Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 20

Answer

$2-3\sqrt 2$ It is a scalar.

Work Step by Step

$2-||u||=2-\sqrt {u⋅u}=2-\sqrt {⟨3,3⟩⋅⟨3,3⟩}=2-\sqrt {3(3)+3(3)}=2-\sqrt {18}=2-3\sqrt 2$
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