Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 30



Work Step by Step

We know that the angle between two vectors is: $\theta =\cos^{-1} [ \dfrac{u \cdot v}{||u|| \space ||v|| }]$ Therefore, $||u||=\sqrt{3^2+2^2}=\sqrt{13}$ and $||v||=\sqrt{4^2+0^2}=4$ $\theta =\cos^{-1} [ \dfrac{(3)(4)+(2)(0)}{ 4\sqrt {13}}]=\cos^{-1}[\dfrac{12}{4 \sqrt{13}}]$ So, $\theta =33.69^{\circ}$
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