Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 36



Work Step by Step

We know that the angle between two vectors is: $\theta =\cos^{-1} [ \dfrac{u \cdot v}{||u|| \space ||v|| }]$ Therefore, $u .v=(2)(4)+(-3)(3)=-1$ and $u||=\sqrt{2^2+(-3)^2}=\sqrt{13}$ and $||v||=\sqrt{4^2+3^2}=5$ $\theta =\cos^{-1} [\dfrac{-1}{5 \sqrt{13}}]$ So, $\theta =93.18^{\circ}$
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