Answer
$93.18^{\circ}$
Work Step by Step
We know that the angle between two vectors is:
$\theta =\cos^{-1} [ \dfrac{u \cdot v}{||u|| \space ||v|| }]$
Therefore, $u .v=(2)(4)+(-3)(3)=-1$ and $u||=\sqrt{2^2+(-3)^2}=\sqrt{13}$ and $||v||=\sqrt{4^2+3^2}=5$
$\theta =\cos^{-1} [\dfrac{-1}{5 \sqrt{13}}]$
So, $\theta =93.18^{\circ}$
