Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 24


$2\sqrt {13}$

Work Step by Step

$||u||=\sqrt {u⋅u}=\sqrt {⟨4,-6⟩⋅⟨4,-6⟩}=\sqrt {(4)^2+(-6)^2}=\sqrt {16+36}=\sqrt {52}=2\sqrt {13}$
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