Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.4 - Vectors and Dot Products - 8.4 Exercises - Page 595: 42

Answer

$76.87^{\circ}$

Work Step by Step

We know that the angle between two vectors is: $\theta =\cos^{-1} [ \dfrac{u \cdot v}{||u|| \space ||v|| }]$ Therefore, $||u||=\sqrt{2^2+(-3)^2}=\sqrt{13}$ and $||v||=\sqrt{8^2+3^2}=\sqrt {73}$ $\theta =\cos^{-1} [ \dfrac{(2)(8)+(-3)(3)}{\sqrt {13}\sqrt {73}}]=\cos^{-1}[\dfrac{7 \sqrt{949}}{949}]$ So, $\theta =76.87^{\circ}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.