## Algebra and Trigonometry 10th Edition

$(\frac{u\cdot v}{|v|^2})v$
$u\cdot v=|u||v|~cos~\theta$ $|u|~cos~\theta=\frac{u\cdot v}{|v|}$ The projection of $u$ onto $v$ is $(|u|~cos~\theta)\frac{v}{|v|}$ Then: $proj_vu=(\frac{u\cdot v}{|v|^2})v$