Answer
$x=0$
$x=3$
Work Step by Step
$8x^3-48x^2+72x=0$
$8x(x^2-6x+9)=0$
$8x[x^2-2(3)x+3^2]=0$
$8x(x-3)^2=0$
$8x=0$
$x=0$
$(x-3)^2=0$
$x-3=0$
$x=3$
Check the solutions:
$x=0$:
$8(0)^3-48(0)^2+72(0)=0-0+0=0$
$x=3$:
$8(3)^3-48(3)^2+72(3)=216-432+216=0$
