Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - Cumulative Test for Chapters P-2 - Page 236: 24


$x=0$ $x=3$

Work Step by Step

$8x^3-48x^2+72x=0$ $8x(x^2-6x+9)=0$ $8x[x^2-2(3)x+3^2]=0$ $8x(x-3)^2=0$ $8x=0$ $x=0$ $(x-3)^2=0$ $x-3=0$ $x=3$ Check the solutions: $x=0$: $8(0)^3-48(0)^2+72(0)=0-0+0=0$ $x=3$: $8(3)^3-48(3)^2+72(3)=216-432+216=0$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.