Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - Cumulative Test for Chapters P-2 - Page 236: 15



Work Step by Step

$-(x+3)=14(x-6)$ $-x-3=14x-84$ $-x-14x=-84+3$ $-15x=-81$ $x=\frac{-81}{-15}=\frac{27}{5}$ Check the answer: $-(\frac{27}{5}+3)=14(\frac{27}{5}-6)$ $-\frac{42}{5}=14(-\frac{3}{5})$ $-\frac{42}{5}=-\frac{42}{5}$
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