Answer
$x=3$
$x=-1$
Work Step by Step
$-2x^2+4x+6=0~~$ (Divide both sides of the equation by $-2$):
$x^2-2x-3=0~~$ (Use: $-2x=x-3x$)
$x^2+x-3x-3=0$
$x(x+1)-3(x+1)=0$
$(x-3)(x+1)=0$
$x-3=0$
$x=3$
$x+1=0$
$x=-1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - Cumulative Test for Chapters P-2 - Page 236: 18
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