Answer
$x=\frac{-5+\sqrt {97}}{6}$
$x=\frac{-5-\sqrt {97}}{6}$
Work Step by Step
$3x^2+5x-6=0~~$ ($a=3,b=5,c=-6$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-5±\sqrt {5^2-4(3)(-6)}}{2(3)}=\frac{-5±\sqrt {97}}{6}$
$x=\frac{-5+\sqrt {97}}{6}$ or $x=\frac{-5-\sqrt {97}}{6}$
