Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - Cumulative Test for Chapters P-2 - Page 236: 20


$x=\frac{-5+\sqrt {97}}{6}$ $x=\frac{-5-\sqrt {97}}{6}$

Work Step by Step

$3x^2+5x-6=0~~$ ($a=3,b=5,c=-6$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-5±\sqrt {5^2-4(3)(-6)}}{2(3)}=\frac{-5±\sqrt {97}}{6}$ $x=\frac{-5+\sqrt {97}}{6}$ or $x=\frac{-5-\sqrt {97}}{6}$
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