Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - Cumulative Test for Chapters P-2 - Page 236: 16



Work Step by Step

$\frac{1}{x-2}=\frac{10}{4x+3}$ $1(4x+3)=10(x-2)$ $4x+3=10x-20$ $4x-10x=-20-3$ $-6x=-23$ $x=\frac{-23}{-6}=\frac{23}{6}$ Check the solution: $\frac{1}{\frac{23}{6}-2}=\frac{10}{4(\frac{23}{6})+3}$ $\frac{1}{\frac{11}{6}}=\frac{10}{\frac{46}{3}+3}$ $1·\frac{6}{11}=\frac{10}{\frac{55}{3}}$ $\frac{6}{11}=10·\frac{3}{55}$ $\frac{6}{11}=\frac{6}{11}$
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