Answer
See graph
Work Step by Step
At $y=0$:
$$x-3(0)+12=0$$ $$x=-12$$
Thus, a point is at $(-12,0)$.
At $x=0$:
$$0-3y+12=0$$ $$-3y=-12$$ $$y=4$$
Thus, another point is at $(0,4)$.
Plotting the two points and drawing a straight passing them, the sketch of the graph is as shown.
