Answer
$x=\frac{-9+\sqrt {69}}{6}$
$x=\frac{-9-\sqrt {69}}{6}$
Work Step by Step
$3x^2+9x+1=0~~$ ($a=3,b=9,c=1$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-9±\sqrt {9^2-4(3)(1)}}{2(3)}=\frac{-9±\sqrt {69}}{6}$
$x=\frac{-9+\sqrt {69}}{6}$ or $x=\frac{-9-\sqrt {69}}{6}$
