Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 153: 80


Solutions: $x=-\frac{1}{4}+\frac{\sqrt {71}}{4}i$ $x=-\frac{1}{4}-\frac{\sqrt {71}}{4}i$

Work Step by Step

$6x^2+3x+27=0~~$ ($a=6,b=3,c=27$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-3±\sqrt {3^2-4(6)(27)}}{2(6)}=\frac{-3±\sqrt {-639}}{12}=\frac{-3±3\sqrt {71}i}{12}=-\frac{1}{4}±\frac{\sqrt {71}}{4}i$ $x=-\frac{1}{4}+\frac{\sqrt {71}}{4}i$ or $x=-\frac{1}{4}-\frac{\sqrt {71}}{4}i$
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