Answer
Solutions:
$x=\frac{2}{3}+\sqrt 2$
$x=\frac{2}{3}-\sqrt 2$
Work Step by Step
$9x^2-12x=14$
$9x^2-12x-14=0~~$ ($a=9,b=-12,c=-14$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-12)±\sqrt {(-12)^2-4(9)(-14)}}{2(9)}=\frac{12±\sqrt {648}}{18}=\frac{12±18\sqrt {2}}{18}=\frac{2±3\sqrt {2}}{3}=\frac{2}{3}±\sqrt 2$
