Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 153: 56


Solutions: $x=\frac{2}{3}+\sqrt 2$ $x=\frac{2}{3}-\sqrt 2$

Work Step by Step

$9x^2-12x=14$ $9x^2-12x-14=0~~$ ($a=9,b=-12,c=-14$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-12)±\sqrt {(-12)^2-4(9)(-14)}}{2(9)}=\frac{12±\sqrt {648}}{18}=\frac{12±18\sqrt {2}}{18}=\frac{2±3\sqrt {2}}{3}=\frac{2}{3}±\sqrt 2$
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