Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 153: 58


Solutions: $x=\frac{1}{2}+\frac{\sqrt {249}}{6}$ $x=\frac{1}{2}-\frac{\sqrt {249}}{6}$

Work Step by Step

$-20-3x+3x^2=0~~$ ($a=3,b=-3,c=-20$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-3)±\sqrt {(-3)^2-4(3)(-20)}}{2(3)}=\frac{3±\sqrt {249}}{6}=\frac{1}{2}±\frac{\sqrt {249}}{6}$
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