Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 153: 49


Solutions: $x=\frac{5}{2}$ $x=-3$

Work Step by Step

$15+x-2x^2=0~~$ ($a=-2,b=1,c=15$) $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-1±\sqrt {1^2-4(-2)(15)}}{2(-2)}=\frac{-1±\sqrt {121}}{4}=\frac{-1±11}{4}$ $x=\frac{10}{4}=\frac{5}{2}$ or $x=\frac{-12}{4}=-3$
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