Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 153: 77


Solutions: $x=1+3i$ $x=1-3i$

Work Step by Step

$x^2-2x+10=0~~$ ($a=1,b=-2,c=10$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-2)±\sqrt {(-2)^2-4(1)(10)}}{2(1)}=\frac{2±\sqrt {-36}}{2}=\frac{2±6i}{2}=1±3i$ $x=1+3i$ or $x=1-3i$
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