Answer
$1.861$ seconds
Work Step by Step
$6.2=-16t^{2}+30t+5.8$
$16t^2-30t+0.4=0$
$t=\frac{30\pm\sqrt{30^2-4(16)(0.4)}}{2(16)}$
$t_1\approx0.01375$
$t_2\approx 1.86125$
Therefore the ball stays in the air for approximately $1.861$ seconds before being caught at $6.2$ ft.
