Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - Review Exercises - Page 153: 79


Solutions: $x=-\frac{1}{2}+\frac{\sqrt 6}{2}i$ $x=-\frac{1}{2}-\frac{\sqrt 6}{2}i$

Work Step by Step

$4x^2+4x+7=0~~$ ($a=4,b=4,c=7$): $x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-4±\sqrt {4^2-4(4)(7)}}{2(4)}=\frac{-4±\sqrt {-96}}{8}=\frac{-4±4\sqrt 6i}{8}=-\frac{1}{2}±\frac{\sqrt 6}{2}i$ $x=-\frac{1}{2}+\frac{\sqrt 6}{2}i$ or $x=-\frac{1}{2}-\frac{\sqrt 6}{2}i$
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