Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 43

Answer

$\frac{1}{(x-1)^2+2^2}$

Work Step by Step

$\frac{1}{x^2-2x+5}=\frac{1}{x^2-2(1)x+1^2-1^2+5}=\frac{1}{(x-1)^2+4}=\frac{1}{(x-1)^2+2^2}$
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