Answer
(a) The graph of the equation $y=x^2+3x-4$ is as shown.
(b) The $x$-intercepts from the graph are $(-4,0)$ and $(1,0)$.
(c) The solution is $x=-4,1$.
(d) The result from part c is the same as the $x$-intercepts of the graph.
Work Step by Step
(a) The graph of the equation $y=x^2+3x-4$ is as shown.
(b) The $x$-intercepts from the graph are $(-4,0)$ and $(1,0)$.
(c) Setting $y=0$:
$$0=x^2+3x-4$$
$$0=(x+4)(x-1)$$
$$x+4=0$$
$$x=-4$$
$$x-1=0$$
$$x=1$$
Thus, the solution is $x=-4,1$.
(d) The result from part c is the same as the $x$-intercepts of the graph.
