Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 50


$\frac{1}{\sqrt {25-(x+3)^2}}$

Work Step by Step

$\frac{1}{\sqrt {16-6x-x^2}}=\frac{1}{\sqrt {25-(x^2+6x+9)}}=$$\frac{1}{\sqrt {25-(x+3)^2}}$
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