Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 40

Answer

No real solutions

Work Step by Step

$-x^2+x-1=0$ $x^2-x+1=0$ $x^2-x+\frac{1}{4}=-1+\frac{1}{4}$ $(x-\frac{1}{2})^2=-\frac{3}{4}$ A square of a real value cannot be negative. Hence no real soultions.
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