Answer
{$-4-\sqrt 2, -4+\sqrt 2$}
Work Step by Step
$x^2+8x+14=0$
$x^2+8x+16=2$
$(x+4)^2=2$
$x+4=+\sqrt 2 or -\sqrt 2$
x = {$-4-\sqrt 2, -4+\sqrt 2$}
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 36
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