Answer
{$\frac{1-3\sqrt 2}{2}, \frac{1+3\sqrt 2}{2}$}
Work Step by Step
$(2x-1)^2=18$
$2x-1 = +\sqrt {18} or -\sqrt {18} = +3\sqrt {2} or -3\sqrt {2}$
$2x = 1+3\sqrt {2} or 1-3\sqrt {2}$
x = {$\frac{1-3\sqrt 2}{2}, \frac{1+3\sqrt 2}{2}$}
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 110: 29
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