Solutions: $x=-2+\sqrt 2$ $x=-2-\sqrt 2$
Work Step by Step
$x^2+4x+2=0$ $x^2+2(2)x+2^2+2=2^2$ $(x+2)^2=4-2$ $(x+2)^2=2$ $x+2=±\sqrt 2$ $x=-2+\sqrt 2$ or $x=-2-\sqrt 2$
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