#### Answer

$\frac{9}{x+4}$

#### Work Step by Step

$\frac{8}{x+4}$-$\frac{3}{3x+12}$
$\frac{8}{x+4}$-$\frac{3}{3(x+4)}$=
$\frac{8*3}{(x+4)*3}$+$\frac{3}{3*(x+4)}$=
$\frac{24+3}{3(x+4)}$=$\frac{27}{3(x+4)}$=
$\frac{9}{x+4}$

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

$\frac{9}{x+4}$

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