#### Answer

3

#### Work Step by Step

$\frac{7x}{x-3}$-$\frac{4x+9}{x-3}$=
$\frac{7x-(4x+9)}{x-3}$=
$\frac{7x-4x-9}{x-3}$=$\frac{3x-9}{x-3}$=$\frac{3(x-3)}{x-3}$ = 3

Published by
Pearson

ISBN 10:
0321726391

ISBN 13:
978-0-32172-639-1

3

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