Answer
$\frac{-5y+8}{3y}$
Work Step by Step
$\frac{-y+1}{y}$-$\frac{2y-5}{3y}$=
$\frac{3(-y+1)}{3y}$-$\frac{2y-5}{3y}$=
$\frac{-3y+3-2y+5}{3y}$=
$\frac{-5y+8}{3y}$
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