Answer
0
Work Step by Step
$\frac{9}{x-3}$+$\frac{9}{3-x}$=
$\frac{9}{x-3}$+$\frac{9(-1)}{(3-x)(-1)}$=
$\frac{9}{x-3}$+$\frac{-9}{x-3}$=
$\frac{9-9}{x-3}$=0
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