Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set: 24

Answer

$\frac{16-6x}{2x-3}$

Work Step by Step

$\frac{7}{2x-3}$-3=$\frac{7}{2x-3}$-3 $\frac{2x-3}{2x-3}$= $\frac{7-3(2x-3)}{2x-3}$=$\frac{7-6x+9}{2x-3}$= $\frac{16-6x}{2x-3}$
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