Answer
$\frac{16-6x}{2x-3}$
Work Step by Step
$\frac{7}{2x-3}$-3=$\frac{7}{2x-3}$-3 $\frac{2x-3}{2x-3}$=
$\frac{7-3(2x-3)}{2x-3}$=$\frac{7-6x+9}{2x-3}$=
$\frac{16-6x}{2x-3}$
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