Answer
$\frac{-y-4}{y+3}$
Work Step by Step
$\frac{y+2}{y+3}$-2
=$\frac{y+2}{y+3}$-2 ($\frac{y+3}{y+3}$)
=$\frac{y+2-2(y+3)}{y+3}$
=$\frac{y+2-2y-6}{y+3}$
=$\frac{y-2y+2-6}{y+3}$
=$\frac{-y-4}{y+3}$
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