Answer
$\frac{10y+5-y^{3}}{y^{2}(2y+1)}$
Work Step by Step
$\frac{5}{y^{2}}$-$\frac{y}{2y+1}$=
$\frac{5(2y+1)}{y^{2}(2y+1)}$-$\frac{y*y^{2}}{(2y+1)y^{2}}$=
$\frac{5(2y+1)-y^{3}}{y^{2}(2y+1)}$=
$\frac{10y+5-y^{3}}{y^{2}(2y+1)}$