Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 810: 37

Please see the graph.

$F(x)=(x+1/2)^2-2 $ Axis of symmetry: $F(x)=(x+1/2)^2-2$ $F(x)=(x- -1/2)^2-2$ $x=-1/2$ Vertex: $F(x)=(x+1/2)^2-2$ $F(-1/2)=(-1/2+1/2)^2-2$ $F(-1/2)=(0)^2-2$ $F(-1/2)=-2$ The red line is the function $F(x)=(x+1/2)^2-2$, the line at $x=-1/2$ is the axis of symmetry, and the point $(-1/2,-2)$ is the vertex.