Answer
Please see the graph.
Work Step by Step
$f(x)=2(x+3)^2 $
Axis of symmetry:
$f(x)=2(x+3)^2$
$f(x)=2(x- -3)^2$
$x=-3$
Vertex:
$f(x)=2(x+3)^2$
$f(-3)=2(-3+3)^2$
$f(-3)=2*(0)^2$
$f(-3)=0$
The red line is the function $f(x)=2(x+3)^2$, the line at $x=-3$ is the axis of symmetry, and the point $(-3,0)$ is the vertex.
