Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 810: 32

Please see the graph.

$f(x)=−(x-2)^2-6 $ Axis of symmetry: $f(x)=−(x-2)^2-6$ $f(x)=−(x−2)^2-6$ $x=2$ Vertex: $f(x)=−(x-2)^2-6$ $f(2)=−(2-2)^2-6$ $f(2)=−(0)^2-6$ $f(2)=0-6$ $f(2)=-6$ The red line is the function $f(x)=−(x-2)^2-6$, the line at $x=2$ is the axis of symmetry, and the point $(2,-6)$ is the vertex.