Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 810: 30

Please see the graph.

$g(x) = 4(x-4)^2+2$ Axis of symmetry: $g(x) = 4(x-4)^2+2$ $g(x) = 4(x- 4)^2+2$ $x=4$ Vertex: $g(x) = 4(x-4)^2+2$ $g(4) = 4(4-4)^2+2$ $g(4) = 4(0)^2+2$ $g(4) = 4*0+2$ $g(4) = 0+2$ $g(4) = 2$ The red line is the function $g(x)=4(x-4)^2+2$, the green line at $x=4$ is the axis of symmetry, and the point $(4,2)$ is the vertex.