Answer
Please see the graph.
Work Step by Step
$F(x)=-4*x^2$
Axis of symmetry:
$F(x)=-4*x^2$
$F(x)=-4*(x-0)^2$
$x=0$
Vertex:
$F(x)=-4*x^2$
$F(0)=-4*(0^2)$
$F(0)=-4*0$
$F(0)=0$
The red line is the function $F(x)=-4*x^2$, the orange line of $x=0$ is the axis of symmetry, and the point $(0,0)$ is the vertex of the function.