Chapter 11 - Section 11.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 810: 34

Please see the graph.

$G(x)=1/5*(x+4)^2+3 $ Axis of symmetry: $G(x)=1/5*(x+4)^2+3$ $G(x)=1/5*(x− -4)^2+3$ $x=-4$ Vertex: $G(x)=1/5*(x+4)^2+3$ $G(-4)=1/5*(-4+4)^2+3$ $G(-4)=1/5*(0)^2+3$ $G(-4)=0+3$ $G(-4)=3$ The red line is the function $G(x)=1/5*(x+4)^2+3$, the line at $x=-4$ is the axis of symmetry, and the point $(-4,3)$ is the vertex.