Answer
Please see the graph.
Work Step by Step
$H(x)=2x^2$
Axis of symmetry:
$H(x)=2x^2$
$H(x)=2(x-0)^2$
$x=0$
Vertex:
$H(x)=2x^2$
$H(0)=2*(0^2)$
$H(0)=2*0$
$H(0)=0$
The red line is the function $H(x)=2x^2$, the orange line of $x=0$ is the axis of symmetry, and the point $(0,0)$ is the vertex of the function.
