Answer
(-infinity, $-5/3)$ U $(7/2$, infinity)
Work Step by Step
$(2x-7)(3x+5)>0$
$(2x-7)(3x+5)=0$
$2x-7=0$
$2x=7$
$2x/2=7/2$
$x=7/2$
$3x+5=0$
$3x=-5$
$3x/3=-5/3$
$x=-5/3$
(-infinity, $-5/3)$
$(-5/3, 7/2)$
$(7/2$, infinity)
Let $x=-3$, $x=0$, $x=10$
$x=-3$
$(2x-7)(3x+5)>0$
$(2*-3-7)(3*-3+5)>0$
$(-6-7)(-9+5)>0$
$-13*-4>0$
$52 >0$ (true)
$x=0$
$(2x-7)(3x+5)>0$
$(2*0-7)(3*0+5)>0$
$(0-7)(0+5)>0$
$-7*5>0$
$-35>0$ (false)
$x=10$
$(2x-7)(3x+5)>0$
$(2*10-7)(3*10+5)>0$
$(20-7)(30+5)>0$
$13*35>0$
$455 >0$ (true)
