Answer
$(-4, -2)$
Work Step by Step
$4/(y+2) < -2$
Denominator is zero when $y=-2$
$4/(y+2) < -2$
$4/(y+2) = -2$
$4*(y+2)/(y+2) = -2*(y+2)$
$4=-2y-4$
$8=-2y$
$8/-2 = -2y/-2$
$-4=y$
(-infinity, $-4)$
$(-4, -2)$
$(-2$, infinity)
Let $y=-10$, $y=-3$, and $y=0$
$y=-10$
$4/(y+2) < -2$
$4/(-10+2) < -2$
$4/-8 < -2$
$-1/2 < -2$ (false)
$y=-3$
$4/(y+2) < -2$
$4/(-3+2) < -2$
$4/-1 < -2$
$-4 < -2$ (true)
$y=0$
$4/(y+2) < -2$
$4/(0+2) < -2$
$4/2 < -2$
$2 < -2$ (false)
