Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 11 - Section 11.4 - Nonlinear Inequalities in One Variable - Exercise Set - Page 799: 43

Answer

(-infinity, $-5)$ U $(-1, 1)$ U $(5$, infinity)

Work Step by Step

$x^4-26x^2+25\geq0$ $x^4-25x^2-x^2+25 \geq 0$ $x^2(x^2-25)-1(x^2-25)\geq 0$ $(x^2-1)(x^2-25)\geq 0$ $(x+1)(x-1)(x-5)(x+5)\geq 0$ $(x+1)(x-1)(x-5)(x+5)= 0$ $x+1=0$ $x=-1$ $x-1=0$ $x=1$ $x-5=0$ $x=5$ $x+5=0$ $x=-5$ (-infinity, $-5)$ $(-5, -1)$ $(-1, 1)$ $(1, 5)$ $(5$, infinity) Let $x=-10$, $x=-3$, $x=0$, $x=3$, $x=10$ $x=-10$ $(x+1)(x-1)(x-5)(x+5)\geq 0$ $(-10+1)(-10-1)(-10-5)(-10+5)\geq 0$ $-9*-11*-15*-5 \geq 0$ $7425 \geq 0$ (true) $x=-3$ $(x+1)(x-1)(x-5)(x+5)\geq 0$ $(-3+1)(-3-1)(-3-5)(-3+5)\geq 0$ $-2*-4*-8*2 \geq 0$ $-128 \geq 0$ (false) $x=0$ $(x+1)(x-1)(x-5)(x+5)\geq 0$ $(0+1)(0-1)(0-5)(0+5)\geq 0$ $1*-1*-5*5 \geq 0$ $25 \geq 0$ (true) $x=3$ $(x+1)(x-1)(x-5)(x+5)\geq 0$ $(3+1)(3-1)(3-5)(3+5)\geq 0$ $4*2*-2*8 \geq 0$ $-128 \geq 0$ (false) $x=10$ $(x+1)(x-1)(x-5)(x+5)\geq 0$ $(10+1)(10-1)(10-5)(10+5)\geq 0$ $11*9*5*15 \geq 0$ $7425 \geq 0$ (true)
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