Answer
(-infinity, $3)$
Work Step by Step
$(x-3)/(x+2) \leq0$
Denominator is zero when $x=-2$
$(x-3)/(x+2) \leq0$
$(x-3)/(x+2) =0$
$(x-3)*(x+2)/(x+2) =0*(x+2)$
$x-3=0$
$x=3$
(-infinity, $3)$
$(3$, infinity)
Let $x=0$ and $x=5$
$x=0$
$(x-3)/(x+2) \leq0$
$(0-3)/(0+2) \leq0$
$-3/2 \leq 0$ (true)
$x=5$
$(x-3)/(x+2) \leq0$
$(5-3)/(5+2) \leq0$
$2/7 \leq 0$ (false)