Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - Chapter Test - Page 491: 34

Answer

$x\approx 4.780$

Work Step by Step

Use the Power Rule of logarithms to obtain: \begin{align*} \ln{x^3}-\ln2&=4 \end{align*} Use the Quotient Rule of logarithms to obtain: \begin{align*} \ln{\left(\frac{x^3}{2}\right)}&=4 \end{align*} Recall: $$\ln{x}=n \longleftrightarrow e^n=x$$ Use the definition above to obtain: \begin{align*} e^4&=\frac{x^3}{2}\\\\ 2(e^4)&=\frac{x^3}{4} \cdot 4\\\\ 2e^4&=x^3\\\\ \sqrt[3]{2e^4}&=\sqrt[3]{x^3}\\\\ \sqrt[3]{2e^4}&=x\\\\ x&=\sqrt[3]{2e^4}\\\\ x&\approx 4.780\end{align*}
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