Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - Chapter Test - Page 491: 23

Answer

$\dfrac{4}{9}$

Work Step by Step

Note that: $$27=3^3$$ and $$81=3^4$$ Thus, the given equation is equivalent to: $$\left(3^3\right)^{3x}=3^4$$ Use the rule $\left(a^m\right)^n=a^{mn}$ to obtain: \begin{align*} 3^{3\cdot 3x}&=3^4\\ 3^{9x}&=3^4 \end{align*} Use the rule $a^m=a^n \longrightarrow m=n$ to obtain: \begin{align*} 9x&=4\\\\ \frac{9x}{9}&=\frac{4}{9}\\\\ x&=\frac{4}{9} \end{align*}
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