Answer
$\log_2{2916}$
Work Step by Step
Recall:
\begin{align*}n \cdot \log_a{b}&=\log_a{\left(b^n\right)} &\text{( Power Rule)}\\\\
\log_a{b}+\log_a{c}&=\log_a{bc} &\text{(Product Rule)}\\\\
\log_a{b}-\log_a{c}&=\log_a{\frac{b}{c}} &\text{(Quotient Rule)}\end{align*}
Use the Power Rule to obtain:
\begin{align*}
&=\log_2{4}+\log_2{9^3}\\
&=\log_2{4}+\log_2{729}
\end{align*}
Use the Product Rule to obtain:
\begin{align*}
&=\log_2{4(729)}\\
&=\log_2{2916}
\end{align*}
