Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 7 - Exponential and Logarithmic Functions - Chapter Test - Page 491: 31

Answer

$x=\dfrac{e}{2}\approx 1.359$

Work Step by Step

Use the Product Rule to obtain: \begin{align*} \ln{\left(2\cdot x\right)}&=1\\ \ln{2x}&=1 \end{align*} Recall: $$\ln{x}=n \longrightarrow e^n=x$$ Use the definition above to obtain: \begin{align*} \ln{2x}&=1\\\\ e^1&=2x\\\\ e&=2x\\\\ \frac{e}{2}&=\frac{2x}{2}\\\\ \frac{e}{2}&=x\\\\ x&\approx 1.359 \end{align*}
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